(2^2x+1)=160

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Solution for (2^2x+1)=160 equation:



(2^2x+1)=160
We move all terms to the left:
(2^2x+1)-(160)=0
We get rid of parentheses
2^2x+1-160=0
We add all the numbers together, and all the variables
2^2x-159=0
We move all terms containing x to the left, all other terms to the right
2^2x=159
x=159/1
x=159

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